Solution of problem 23 of the collection on general che

Affiliates: 0,01 $ — how to earn
Pay with:
i agree with "Terms for Customers"
Sold: 0
Refunds: 0

Uploaded: 22.09.2016
Content: 23_Glinka.jpg (25,02 kB)


23. The equivalent mass of the metal is 12 g / mol. What is the equivalent mass of its oxide equal to: a) 24 g / mol; B) can not be determined; C) 20 g / mol?


No feedback yet.
1 month 3 months 12 months
0 0 0
0 0 0
In order to counter copyright infringement and property rights, we ask you to immediately inform us at the fact of such violations and to provide us with reliable information confirming your copyrights or rights of ownership. Email must contain your contact information (name, phone number, etc.)