# Solution V00 D5 (Fig 0 0 conv) teormeh Targ SM 1989

Sold: 0
Refunds: 0

Content: d5-00.zip (29,85 kB)
Loyalty discount! If the total amount of your purchases from the seller TerMaster more than:
 50 \$ the discount is 10% show all discounts 1 \$ the discount is 1%

# Seller

TerMaster information about the seller and his items

Seller will give you a gift certificate in the amount of 24,91 RUB for a positive review of the product purchased..

# Description

V00 D5 - solution to the problem of termehu Targ SM 1989. Conditions to task Dynamics 5: Homogeneous horizontal platform (circular radius R or rectangular with sides of R and 2R, where R = 1,2 m) m1 = weight of 24 kg is rotated with an angular velocity omega0 = 10 s-1 around the vertical axis z, spaced from the center of mass C platform in the distance OC = b (Fig. D5.0 -D5.9, Table. D5); Dimensions for all rectangular platforms is shown in Fig. D5.0a (top view). At time t0 = 0 the chute platform begins to move (under the influence of internal forces) load D m2 = mass of 8 kg law s = AD = F (t) where s is expressed in meters, t - in seconds. At the same time the platform starts to operate a pair of forces with the moment M (given in newton, with M <0, its direction is opposite to that shown in the figures). Determine neglecting the mass of the shaft, the dependence of omega = f (t), t. E. Angular velocity of the platform, as a function of time. In all the figures shown in the load position D, wherein s> 0 (when s <0, the weight is on the other side of the point A). Portraying drawing the problem, hold the z-axis at a predetermined distance OC = b from the center of S.