Решение Д5 В65 (рис 6 усл 5) теормех Тарг С.М. 1989 г

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Uploaded: 03.07.2013
Content: d5-65.zip 28,83 kB
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Решение Д5 В65 (рис 6 усл 5) теормех Тарг С.М. 1989 г Решение Д5 В65 (рис 6 усл 5) теормех Тарг С.М. 1989 г

Сразу после оплаты вам будет предложена ссылка для скачивания задачи Д5 Вариант 65 (рисунок 6 условие 5) по теормеху из решебника Тарга С.М. 1989 года для студентов-заочников машиностроительных, строительных, транспортных, приборостроительных специальностей высших учебных заведений. Задача выполнена в формате word, запакована в архив zip.

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A5 B65 - solution to the problem of termehu Targa SM 1989. Conditions to task Dynamics 5: Homogeneous horizontal platform (circular radius R or rectangular with sides of R and 2R, where R = 1,2 m) m1 = weight of 24 kg is rotated with an angular velocity omega0 = 10 s-1 around the vertical axis z, spaced from the center of mass C platform in the distance OC = b (Fig. D5.0 -D5.9, Table. D5); Dimensions for all rectangular platforms is shown in Fig. D5.0a (top view). At time t0 = 0 the chute platform begins to move (under the influence of internal forces) load D m2 = mass of 8 kg law s = AD = F (t) where s is expressed in meters, t - in seconds. At the same time the platform starts to operate a pair of forces with the moment M (given in newton, with M <0, its direction is opposite to that shown in the figures). Determine neglecting the mass of the shaft, the dependence of omega = f (t), t. E. Angular velocity of the platform, as a function of time. In all the figures shown in the load position D, wherein s> 0 (when s <0, the weight is on the other side of the point A). Portraying drawing the problem, hold the z-axis at a predetermined distance OC = b from the center of S.

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