решение задачи по физике

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Скорость тела, движущегося прямолинейно, меняется по закону v = A+Bt+Ct2, где A = 1 м/с; B = 3 м/с2; C = 6 м/с3. Какое расстояние пройдет тело к моменту времени, когда его ускорение станет равным a = 27 м/с2?

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