Solution of task 13.6.25 from the collection of Kepe OE
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A body weighing m = 5 kg is suspended from the spring. Determine the coefficient of spring stiffness if the differential equation of rectilinear translational motion of the body has the form x + 6x + 40x = 5 sin 15t. (Answer 200)
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- Content type File
- Content description 20,98 kB
- Updated on the site 02.06.2017
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Solution of task 13.6.25 from the collection of Kepe OE
Cumulative discount
| 200 $ | the discount is 15% |
| 100 $ | the discount is 10% |
| 50 $ | the discount is 7% |
| 20 $ | the discount is 5% |
| 10 $ | the discount is 3% |
| 5 $ | the discount is 2% |
| 1 $ | the discount is 1% |
Amount of purchases from the seller: $
Your discount: %
Cumulative discount
| 200 $ | the discount is 15% |
| 100 $ | the discount is 10% |
| 50 $ | the discount is 7% |
| 20 $ | the discount is 5% |
| 10 $ | the discount is 3% |
| 5 $ | the discount is 2% |
| 1 $ | the discount is 1% |
Amount of purchases from the seller: $
Your discount: %
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