0731. Solving a chemistry problem
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34. 25 ml of 0.1 N silver nitrate solution is poured into two glasses. The solutions are connected by a salt bridge containing potassium nitrate, and identical silver electrodes are introduced into them. 25 ml of lead nitrate solution was added to one of the glasses, resulting in a potential difference of 13 mV between the electrodes. Calculate the content of silver impurities in lead if a solution of lead nitrate is prepared by dissolving 25 g of lead in nitric acid and diluting the resulting solution to 250 ml.
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- Content type File
- Content description 23,16 kB
- Added to the site 18.11.2023
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If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.
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