08. Solving a chemistry problem

08. Solving a chemistry problem

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1. Equivalent electrical conductivity of 1.59 ⋅10-4 M acetic acid at 25°C λ = 12.77 S⋅cm2/mol-equiv. Calculate the dissociation constant K and the specific electrical conductivity of the solution (S⋅cm-1), if the ion mobility λ0H = 349.8 S⋅cm2/mol-equiv. and λ0CH3COO– = 40.9 S⋅cm2/mol-eq.

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  • Content type File
  • Content description 17,09 kB
  • Added to the site 26.10.2023
If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.

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