32. Solving a chemistry problem
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10. When one mole of C6H5NH2 is mixed with one mole of H2 at 400 K, the following reaction takes place: C6H5NH2 H2 = C6H6 NH3. Upon reaching equilibrium, the reaction mixture contains 0.165 moles of C6H6 and NH3 each. Calculate:
a) the equilibrium constant Kc; b) the amount of C6H6 formed if 0.5 mol C6H5NH2 and 0.5 mol H2 are mixed.
a) the equilibrium constant Kc; b) the amount of C6H6 formed if 0.5 mol C6H5NH2 and 0.5 mol H2 are mixed.
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- Content type File
- Content description 11,19 kB
- Added to the site 06.04.2023
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If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.
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32. Solving a chemistry problem
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