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A car of mass m = 1 t moves along a horizontal section of the road. The path traveled by him changes according to the law s = At Bt ^ 2, where A = 1 m / s; B = 1 m/s^2. At what point in time t will the engine power be equal to N = 70 kW, if the resistance force in this case turns out to be equal to Fc = 12 kN?
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- Updated on the site 01.06.2024
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A detailed solution with a brief note of the conditions, formulas and laws used in the solution, the derivation of the calculation formula and the answer.
If you have any questions about the solution, write. I try to help.
If you have any questions about the solution, write. I try to help.
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