- Arts & Culture 6855
- Business & Economics 669
- Computers 318
- Dictionaries & Encyclopedias 81
- Education & Science 78567
- Abstracts 73
- Astrology 5
- Biology 8
- Chemistry 4961
- Coursework 15614
- Culture 8
- Diplomas 325
- Drawings 1597
- Ecology 5
- Economy 81
- English 81
- Ethics, Aesthetics 3
- For Education Students 16856
- Foreign Languages 11
- Geography 3
- Geology 1
- History 37
- Maps & Atlases 3
- Mathematics 13952
- Musical Literature 2
- Pedagogics 21
- Philosophy 22
- Physics 15123
- Political Science 5
- Practical Work 59
- Psychology 65
- Religion 4
- Russian and culture of speech 8
- School Textbooks 7
- Sociology 9
- Summaries, Cribs 88
- Test Answers 164
- Tests 8847
- Textbooks for Colleges and Universities 32
- Theses 7
- To Help Graduate Students 13
- To Help the Entrant 38
- Vetting 408
- Works 13
- Информатика 8
- Engineering 758
- Fiction 711
- House, Family & Entertainment 86
- Law 132
- Website Promotion 72
4. Solving a chemistry problem
Content: 12ее.zip 120,66 kB
Product description
12. According to the dependence of the saturated vapor pressure on the temperature and density of a given substance A (dsolid and dl in kg / m3) at the triple point (tr.t.):
1) plot lgP versus 1/T;
2) determine the coordinates of the triple point from the graph;
3) calculate the average heat of evaporation and sublimation;
4) plot the dependence of saturated steam pressure on temperature;
5) determine the heat of fusion of a substance at the triple point temperature;
6) calculate dT/dp for the melting process at the triple point temperature;
7) calculate the melting point of the substance at pressure p, Pa;
8) calculate the change in entropy, Gibbs and Helmholtz energy, enthalpy and internal energy for the process of sublimation of 1 mol of substance at the triple point;
9) determine the number of thermodynamic degrees of freedom at the following values of temperature and pressure:
a) Ttr.t , ptr.t;
b) Tntc, p= 1.013 x 105 Pa;
c) Tntk, ptr.t
Option Solid state Liquid state Conditions
T,K R,Pa T,K R,Pa
12,183.2
188.0
196.2
199.2
203.7 333.3
586.5
1850
3000
5305 201
203.7
214
216
230.2
244.0 4665.6
5305
7198
7998
13328
21728 M=64
P=1000 .105 Pa
dtv =1600
j = 1560
Additional information
If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.
Feedback
0| Period | |||
| 1 month | 3 months | 12 months | |
| 0 | 0 | 0 | |
| 0 | 0 | 0 | |