58. Solving a chemistry problem
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2. Determine the molar mass of the equivalent of the oxidizing agent and reducing agent in the reaction:
MnO2(tv) 2I– 4H = Mn2 I2 2H2O
MnO2(tv) 2I– 4H = Mn2 I2 2H2O
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- Content type File
- Content description 15,38 kB
- Added to the site 15.01.2023
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If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.
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58. Solving a chemistry problem
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