43. Solving a chemistry problem
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365. The reaction is expressed by the schemes:
KMnO4 HCl = KCl MnCl2 Cl2 H2O,
Zn HNO3, razb \u003d Zn (NO3) 2 N2O H2O.
Write electronic equations. Arrange the coefficients in the reaction equations. For each reaction, indicate which substance is the oxidizing agent, which is the reducing agent; which substance is oxidized and which is reduced.
KMnO4 HCl = KCl MnCl2 Cl2 H2O,
Zn HNO3, razb \u003d Zn (NO3) 2 N2O H2O.
Write electronic equations. Arrange the coefficients in the reaction equations. For each reaction, indicate which substance is the oxidizing agent, which is the reducing agent; which substance is oxidized and which is reduced.
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- Content type File
- Content description 15,21 kB
- Added to the site 17.02.2023
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If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.
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43. Solving a chemistry problem
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