4. A thin homogeneous rod AB of mass m = 1.0 kg moves p

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4. A thin homogeneous rod AB of mass m = 1.0 kg moves progressively with acceleration a = 2.0 m / s2 under the action of two forces F1 and F2. The distance between the points of application of these forces is b = 20 cm. In addition, it is known that F2 = 5.0 N. Find the length of the rod.

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Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)

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