49. Solution to Chemistry Problem
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3. Calculate the standard heat (enthalpy) of formation of a compound if its heat of combustion ΔН0сгор (Table 2) is known at T=298 K and p=1.0133*I05 Pa. Heats of combustion of simple substances:
С О2 = СO2 (g) - 393.79*106 J/kmol
Н2 1/2O2 = Н2О (g) - 286.26*106 J/kmol
option Reaction of compound formation ΔН0сгор*10-6,
J/kmol
2 3C 3H2 1/2O2=C3H6O(g) -1787.01
С О2 = СO2 (g) - 393.79*106 J/kmol
Н2 1/2O2 = Н2О (g) - 286.26*106 J/kmol
option Reaction of compound formation ΔН0сгор*10-6,
J/kmol
2 3C 3H2 1/2O2=C3H6O(g) -1787.01
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