Solving a problem in physics section 67 point 57 electr
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57. Find the electric field strength E at the point lying in the middle between the point charges Q1 = 8 nC and Q2 = –6 nC. The distance between charges r = 10 cm; ε = 1
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- Content type File
- Content description 43,5 kB
- Updated on the site 01.05.2020
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Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)
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Solving a problem in physics section 67 point 57 electr
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| 12 $ | the discount is 4% |
| 9 $ | the discount is 3% |
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| 3 $ | the discount is 1% |
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Cumulative discount
| 30 $ | the discount is 10% |
| 20 $ | the discount is 7% |
| 18 $ | the discount is 6% |
| 15 $ | the discount is 5% |
| 12 $ | the discount is 4% |
| 9 $ | the discount is 3% |
| 6 $ | the discount is 2% |
| 3 $ | the discount is 1% |
Check your discount
Amount of purchases from the seller: $
Your discount: %