8. The distance between two point charges q1 = 22.5 ∙ 1

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8. The distance between two point charges q1 = 22.5 ∙ 10−6 C and q2 = −44 ∙ 10−6 C is 5 cm. Find the field strength and potential at a point located 3 cm from the positive charge and 4 cm from a negative charge.

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Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)

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