91. Solving a chemistry problem
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3. The heat of dissociation of calcium carbonate by the reaction CaCO3(s)=CaO(s)CO2 at 900 C is 178.0 kJ/mol. Molar heat capacities of substances:
CpCaCO3(s)=104.5 21.92*10-3T-25.94*105T-2 J/mol*deg,
CpCaO(s)=49.63 4.52*10-3T-6.95*105T-2 J/mol*deg,
CpCO2(g)=44.14 9.04*10-3T-8.53*105T-2 J/mol*deg,
derive the equation for the dependence of the heat effect of this reaction on temperature. Determine the amount of heat absorbed during the decomposition of 1 kg of calcium carbonate at 1000 C
CpCaCO3(s)=104.5 21.92*10-3T-25.94*105T-2 J/mol*deg,
CpCaO(s)=49.63 4.52*10-3T-6.95*105T-2 J/mol*deg,
CpCO2(g)=44.14 9.04*10-3T-8.53*105T-2 J/mol*deg,
derive the equation for the dependence of the heat effect of this reaction on temperature. Determine the amount of heat absorbed during the decomposition of 1 kg of calcium carbonate at 1000 C
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