DHS 15.1 - Option 19. Decisions Ryabushko AP
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1. Dana function u (M) = u (x, y, z) and the point M1, M2. Calculate: 1) The derivative of this function in the direction of the point M1 M1M2 vector; 2) grad u (M1)
1.19. u (M) = 3x2yz3, M1 (-2, -3, 1), M2 (5, -2, 0)
2. Calculate the surface integral of the first kind on the surface S, where S - part of the plane (p), cut off by the coordinate planes.
(P): x - y + z = 2
3. Calculate the surface integral of the second kind.
where S - the surface of the cone x2 + z2 = y2 (normal vector n which forms an obtuse angle with the unit vector j), clipping plane y = 0, y = 1.
4. Calculate the flow vector field a (M) through the outer surface of the pyramid formed by plane (p) and the coordinate planes in two ways: a) determination using flow; b) using the formula Ostrogradskii - Gauss.
4.19. and (M) = (2x - z) i + (y - x) j + (x + 2z) k, (p): x - y + z = 2
1.19. u (M) = 3x2yz3, M1 (-2, -3, 1), M2 (5, -2, 0)
2. Calculate the surface integral of the first kind on the surface S, where S - part of the plane (p), cut off by the coordinate planes.
(P): x - y + z = 2
3. Calculate the surface integral of the second kind.
where S - the surface of the cone x2 + z2 = y2 (normal vector n which forms an obtuse angle with the unit vector j), clipping plane y = 0, y = 1.
4. Calculate the flow vector field a (M) through the outer surface of the pyramid formed by plane (p) and the coordinate planes in two ways: a) determination using flow; b) using the formula Ostrogradskii - Gauss.
4.19. and (M) = (2x - z) i + (y - x) j + (x + 2z) k, (p): x - y + z = 2
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Detailed solution. Designed in PDF format for easy viewing of IDZ solutions on smartphones and PCs. In MS Word (doc format) sent additionally.
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