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1. Find the equation of the tangent plane and the normal to the given surface S at the point M0 (x0, y0, z0)
1.20 S: x2 - y2 - z2 + xz + 4x = -5, M0 (-2, 1, 0)
2. Find the second partial derivatives of the functions. Ensure that z "xy = z" yx
2.20 z = ln (4x2 - 5y3)
3. To verify whether the above equation the function u.
4. Examine the following function extremum.
4.20 z = 2xy - 3x2 - 2y2 + 10
5. Find the maximum and minimum values of the function z = z (x, y) in D, given the limited lines.
5.20 z = x2 + xy - 2, D: y = 4x2 - 4, y = 0
1.20 S: x2 - y2 - z2 + xz + 4x = -5, M0 (-2, 1, 0)
2. Find the second partial derivatives of the functions. Ensure that z "xy = z" yx
2.20 z = ln (4x2 - 5y3)
3. To verify whether the above equation the function u.
4. Examine the following function extremum.
4.20 z = 2xy - 3x2 - 2y2 + 10
5. Find the maximum and minimum values of the function z = z (x, y) in D, given the limited lines.
5.20 z = x2 + xy - 2, D: y = 4x2 - 4, y = 0
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- Added to the site 26.07.2020
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Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)
For the convenience of viewing IDZ solutions on smartphones, an additional file in PDF format is sent
For the convenience of viewing IDZ solutions on smartphones, an additional file in PDF format is sent
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