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At 1.15 rectilinear segment AB, which connects the two light sources A (power p) and B (force q), find the point M illuminated by the weakest if | AB | = a. (Illumination is inversely proportional to the square of the distance from the light source.)
2. Carry out a full investigation of these functions and build their schedules.
2.15 y = -ln ((1 + x) / (1 - x))
3. Carry out a full investigation of these functions and build their schedules.
3.15 y = ((x - 2) / (x + 1)) 2
4. Find the minimum and maximum values of the function y = f (x) on the interval [a; b]
4.15 y = (1 + lnx) / x, [1 / e; e]
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- Content type File
- Content description 121,09 kB
- Updated on the site 08.07.2025
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IDZ 6.4 - Option 15. Decisions Ryabushko AP
Cumulative discount
| 30 $ | the discount is 10% |
| 20 $ | the discount is 7% |
| 18 $ | the discount is 6% |
| 15 $ | the discount is 5% |
| 12 $ | the discount is 4% |
| 9 $ | the discount is 3% |
| 6 $ | the discount is 2% |
| 3 $ | the discount is 1% |
Amount of purchases from the seller: $
Your discount: %
Cumulative discount
| 30 $ | the discount is 10% |
| 20 $ | the discount is 7% |
| 18 $ | the discount is 6% |
| 15 $ | the discount is 5% |
| 12 $ | the discount is 4% |
| 9 $ | the discount is 3% |
| 6 $ | the discount is 2% |
| 3 $ | the discount is 1% |
Amount of purchases from the seller: $
Your discount: %
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