IDZ Ryabushko Option 25 KR "Differential Equations"
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Test "Differential Equations" (2 hours). 345 p.
Solve these differential equations.
1.25 x2y′ = 2xy + 3
2.25 y2 + x2y′ = xyy′
3.25 y′′ = √1 − y′2
4.25 y′′ + 4y = e−2x, y(0) = 0, y′(0) = 0
5.25 y′′ − 3y′ + 2y = 1 + 1/(1 + ex)
Solve these differential equations.
1.25 x2y′ = 2xy + 3
2.25 y2 + x2y′ = xyy′
3.25 y′′ = √1 − y′2
4.25 y′′ + 4y = e−2x, y(0) = 0, y′(0) = 0
5.25 y′′ − 3y′ + 2y = 1 + 1/(1 + ex)
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- Content description 113,67 kB
- Added to the site 20.02.2025
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Detailed solution. Designed in PDF format for easy viewing of IDZ solutions on smartphones. In MS Word (doc format) sent additionally.
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IDZ Ryabushko Option 25 KR "Differential Equations"
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