104. Solving a chemistry problem

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In two reactions of the same order, the difference in activation energies is E2 - E1 = 40 kJ/mol. At a temperature of 293 K, the ratio of the rate constants is equal to k1/k2 = 2. At what temperature will the rate constants become equal?

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  • Content type File
  • Content description 34,14 kB
  • Added to the site 31.08.2022

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If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.

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