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A ball attached to a weightless thread length l1 = 50 cm, is rotated in a horizontal plane about a vertical axis at a speed n1 = 2 v / v. What will be equal to the angular momentum of the ball, if the shortening of the thread is 10 cm, its kinetic energy becomes equal to T2 = 0.48 J?
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- Added to the site 31.05.2022
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A detailed solution with a brief note of the conditions, formulas and laws used in the solution, the derivation of the calculation formula and the answer.
If you have any questions about the solution, write. I will try to help.
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