Solid ball weighing 1 kg and 5 cm radius rotates

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Uploaded: 10.02.2014
Content: 10516.jpg 55,48 kB
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Product description

Solid ball weighing 1 kg and 5 cm radius rotated about an axis passing through its center. The law of rotation of the ball by the equation f = 10 + 5t-2t ^ 2. At a point most remote from the axis of rotation on the ball a force tangential to the surface. To determine this power and braking torque.

Additional information

Task 10516. Detailed solution shorthand terms, formulas, laws used in the decision, the withdrawal of the calculation formula and the response.
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