Solution of problem 10 of the collection on general che
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10. To restore 1.80 g of metal oxide, 883 ml of hydrogen, measured under normal conditions, was consumed. Calculate the equivalent masses of oxide and metal.
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- Content type File
- Content description 9,18 kB
- Added to the site 11.05.2017
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Solution of problem 10 of the collection on general che
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Secure deal
Instant delivery
Cumulative discount
| 200 $ | the discount is 15% |
| 100 $ | the discount is 10% |
| 50 $ | the discount is 7% |
| 20 $ | the discount is 5% |
| 10 $ | the discount is 3% |
| 5 $ | the discount is 2% |
| 1 $ | the discount is 1% |
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Amount of purchases from the seller: $
Your discount: %
Cumulative discount
| 200 $ | the discount is 15% |
| 100 $ | the discount is 10% |
| 50 $ | the discount is 7% |
| 20 $ | the discount is 5% |
| 10 $ | the discount is 3% |
| 5 $ | the discount is 2% |
| 1 $ | the discount is 1% |
Check your discount
Amount of purchases from the seller: $
Your discount: %