Solution of problem 116 of the collection on general ch
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116. To the solution containing 0.20 moles of FeCl3, 0.24 moles of NaOH was added. How many moles of Fe (OH) 3 was formed as a result of the reaction and how many moles of FeCl3 remained in the solution?
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- Content type File
- Content description 66,87 kB
- Added to the site 11.05.2017
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Solution of problem 116 of the collection on general ch
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Cumulative discount
| 200 $ | the discount is 15% |
| 100 $ | the discount is 10% |
| 50 $ | the discount is 7% |
| 20 $ | the discount is 5% |
| 10 $ | the discount is 3% |
| 5 $ | the discount is 2% |
| 1 $ | the discount is 1% |
Check your discount
Amount of purchases from the seller: $
Your discount: %
Cumulative discount
| 200 $ | the discount is 15% |
| 100 $ | the discount is 10% |
| 50 $ | the discount is 7% |
| 20 $ | the discount is 5% |
| 10 $ | the discount is 3% |
| 5 $ | the discount is 2% |
| 1 $ | the discount is 1% |
Check your discount
Amount of purchases from the seller: $
Your discount: %