Solution of problem 624 of the collection on general ch
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624. Write the equations for the half reactions of oxidation and reduction for the following reactions and determine in which cases hydrogen serves as an oxidizer and in which as a reducing agent:
A) 2Al + 6HCl = 2AlCl3 + 3H2
B) 2H2 + O2 = 2H2O
C) 2Na + 2H2O = NaOH + H2
D) BaH2 + 2H2O = Ba (OH) 2 + 2H2
A) 2Al + 6HCl = 2AlCl3 + 3H2
B) 2H2 + O2 = 2H2O
C) 2Na + 2H2O = NaOH + H2
D) BaH2 + 2H2O = Ba (OH) 2 + 2H2
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- Updated on the site 15.05.2017
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Cumulative discount
| 200 $ | the discount is 15% |
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| 10 $ | the discount is 3% |
| 5 $ | the discount is 2% |
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