Solution of problem 629 of the collection of general ch
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629. Complete the reaction equations:
A) KI + Fe2 (SO4) 3 → I2 +
B) KI + CuCl2 → CuCl +
C) SnCl2 + HgCl2 → Hg2Cl2 +
A) KI + Fe2 (SO4) 3 → I2 +
B) KI + CuCl2 → CuCl +
C) SnCl2 + HgCl2 → Hg2Cl2 +
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- Content type File
- Content description 8,67 kB
- Added to the site 15.05.2017
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Solution of problem 629 of the collection of general ch
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| 100 $ | the discount is 10% |
| 50 $ | the discount is 7% |
| 20 $ | the discount is 5% |
| 10 $ | the discount is 3% |
| 5 $ | the discount is 2% |
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Cumulative discount
| 200 $ | the discount is 15% |
| 100 $ | the discount is 10% |
| 50 $ | the discount is 7% |
| 20 $ | the discount is 5% |
| 10 $ | the discount is 3% |
| 5 $ | the discount is 2% |
| 1 $ | the discount is 1% |
Check your discount
Amount of purchases from the seller: $
Your discount: %