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293. Determine the ΔHº298 of the formation of ethylene using the following data:
C2H4 (g) + 3O2 (g) = 2CO2 (g) + 2H2O (g) ΔHº = -1323 kJ
C (graphite) + O2 (g) = CO2 (g.) ΔHº = -393.5 kJ
H2 (g) + ½O2 (g) = H2O (g.) ΔHº = -241.8 kJ
C2H4 (g) + 3O2 (g) = 2CO2 (g) + 2H2O (g) ΔHº = -1323 kJ
C (graphite) + O2 (g) = CO2 (g.) ΔHº = -393.5 kJ
H2 (g) + ½O2 (g) = H2O (g.) ΔHº = -241.8 kJ
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| 200 $ | the discount is 15% |
| 100 $ | the discount is 10% |
| 50 $ | the discount is 7% |
| 20 $ | the discount is 5% |
| 10 $ | the discount is 3% |
| 5 $ | the discount is 2% |
| 1 $ | the discount is 1% |
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