Solution of the problem of the collection of Kep 5.5.16
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Plate ABCD is fixed in a horizontal position by means of hinges and three rods 1, 2 and 3. The weight of the plate 10 G1 = H, the points A and D of the second plate is hinged plate width EF = AD weight and G2 = 8 N. Define force in Terminal 1, when the distance a = 0.4 m.
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- Content type File
- Content description 116,4 kB
- Updated on the site 10.11.2016
Additional description
Immediately after payment you will receive a link to the zip file with the task 5.5.12 (Chapter 1 - statics topic - 5.5: Equilibrium spatial system of parallel forces) on the theoretical mechanics of collection of short tasks Kep OE, JA Viba, OP Grapis, JA Svetinysh and others. Publishing Moscow / Graduate School / 1989, 2009, 2012. The task is made in the format word (typed or hand-written decision in a Word) or in manuscript form in the format gif, packed to the archive zip (open on any PC) .After checking the solutions would be very grateful if you leave your positive feedback.
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Solution of the problem of the collection of Kep 5.5.16
3
Sold <10
0 000 X
Secure deal
Instant delivery
Cumulative discount
| 250 $ | the discount is 15% |
| 50 $ | the discount is 10% |
| 30 $ | the discount is 7% |
| 15 $ | the discount is 5% |
| 5 $ | the discount is 3% |
| 3 $ | the discount is 2% |
| 1 $ | the discount is 1% |
Check your discount
Amount of purchases from the seller: $
Your discount: %
0.04 $ gift card for a positive review
Cumulative discount
| 250 $ | the discount is 15% |
| 50 $ | the discount is 10% |
| 30 $ | the discount is 7% |
| 15 $ | the discount is 5% |
| 5 $ | the discount is 3% |
| 3 $ | the discount is 2% |
| 1 $ | the discount is 1% |
Check your discount
Amount of purchases from the seller: $
Your discount: %
0.04 $ gift card for a positive review