Solution of the problem of the collection of Kep 5.5.16

Solution of the problem of the collection of Kep 5.5.16

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Plate ABCD is fixed in a horizontal position by means of hinges and three rods 1, 2 and 3. The weight of the plate 10 G1 = H, the points A and D of the second plate is hinged plate width EF = AD weight and G2 = 8 N. Define force in Terminal 1, when the distance a = 0.4 m.

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  • Content type File
  • Content description 116,4 kB
  • Added to the site 10.11.2016
Immediately after payment you will receive a link to the zip file with the task 5.5.12 (Chapter 1 - statics topic - 5.5: Equilibrium spatial system of parallel forces) on the theoretical mechanics of collection of short tasks Kep OE, JA Viba, OP Grapis, JA Svetinysh and others. Publishing Moscow / Graduate School / 1989, 2009, 2012. The task is made in the format word (typed or hand-written decision in a Word) or in manuscript form in the format gif, packed to the archive zip (open on any PC) .After checking the solutions would be very grateful if you leave your positive feedback.

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Solution of the problem of the collection of Kep 5.5.16
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Cumulative discount

250 $ the discount is 15%
50 $ the discount is 10%
30 $ the discount is 7%
15 $ the discount is 5%
5 $ the discount is 3%
3 $ the discount is 2%
1 $ the discount is 1%
Check your discount

Amount of purchases from the seller:  $

Your discount:  %

0.05 $ gift card for a positive review

Cumulative discount

250 $ the discount is 15%
50 $ the discount is 10%
30 $ the discount is 7%
15 $ the discount is 5%
5 $ the discount is 3%
3 $ the discount is 2%
1 $ the discount is 1%
Check your discount

Amount of purchases from the seller:  $

Your discount:  %

0.05 $ gift card for a positive review

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