Solution to task 503 from Chertov's for extramural stud
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503. The distance L from the slits to the screen in Young´s experiment is equal to 1 m. Determine the distance between the slits, if N = 10 dark interference fringes fit on a segment of length l = 1 cm. Wavelength λ = 0.7 μm.
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- Content type File
- Content description 19,15 kB
- Added to the site 17.12.2020
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Solution to task 503 from Chertov's for extramural stud
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Sold <10
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Cumulative discount
| 200 $ | the discount is 15% |
| 100 $ | the discount is 10% |
| 50 $ | the discount is 7% |
| 20 $ | the discount is 5% |
| 10 $ | the discount is 3% |
| 5 $ | the discount is 2% |
| 1 $ | the discount is 1% |
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0.04 $ gift card for a positive review
Cumulative discount
| 200 $ | the discount is 15% |
| 100 $ | the discount is 10% |
| 50 $ | the discount is 7% |
| 20 $ | the discount is 5% |
| 10 $ | the discount is 3% |
| 5 $ | the discount is 2% |
| 1 $ | the discount is 1% |
Check your discount
Amount of purchases from the seller: $
Your discount: %
0.04 $ gift card for a positive review