Secure deal
Instant delivery
Product description
52. The two coils wound on a common core. The inductance of the first coil L1 = 0,16 TR, the second - L2 = 1 TR, the second coil resistance R2 = 400 ohms. Determine power current I2 to the second coil, when the current of 0.4 A, the current in the first coil is off for 0,002 s.
Main features
- Content type File
- Content description 38 kB
- Added to the site 06.11.2014
Additional description
Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)
Reviews
No reviews yet
0 000 X
There are no such quantities in stock
By clicking the button, you agree to
terms for buyers
Solving a problem in physics section 33 paragraph 52 el
0 000 X
Secure deal
Instant delivery