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52. The two coils wound on a common core. The inductance of the first coil L1 = 0,16 TR, the second - L2 = 1 TR, the second coil resistance R2 = 400 ohms. Determine power current I2 to the second coil, when the current of 0.4 A, the current in the first coil is off for 0,002 s.
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- Added to the site 06.11.2014
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Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)
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Solving a problem in physics section 33 paragraph 52 el
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