Solving a problem in physics section 33 point 21 molecu
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21. Mercury 3 g is placed between two parallel glass plates. Determine the force that must be applied to flatten to a thickness of drop d = 0,1 mm. Mercury does not wet glass. Mercury density ρ = 13,6 g / cm3, and its surface tension σ = 0,5 N / m.
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- Content type File
- Content description 32 kB
- Updated on the site 27.09.2014
Additional description
Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)
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Cumulative discount
| 30 $ | the discount is 10% |
| 20 $ | the discount is 7% |
| 18 $ | the discount is 6% |
| 15 $ | the discount is 5% |
| 12 $ | the discount is 4% |
| 9 $ | the discount is 3% |
| 6 $ | the discount is 2% |
| 3 $ | the discount is 1% |
Check your discount
Amount of purchases from the seller: $
Your discount: %