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77. Determine the smallest thickness of the crystal plate at half wavelength for λ = 589 nm. if the difference in the refractive indices of the ordinary and extraordinary rays for a given wavelength n0 - ne = 0,17
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- Content type File
- Content description 26 kB
- Added to the site 10.11.2015
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Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)
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