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3. The distance d between the nearest neighbor atoms of the crystal lattice of gold is equal to 0.788 nm. Determine the lattice parameter a, if the face-centered cubic lattice.
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- Content type File
- Content description 34,5 kB
- Added to the site 01.03.2016
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Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)
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