Solving a problem in physics section 68 point 8 electr
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8. The distance between two point charges q1 = 22.5 ∙ 10−6 C and q2 = −44 ∙ 10−6 C is 5 cm. Find the field strength and potential at a point located 3 cm from the positive charge and 4 cm from a negative charge.
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- Content type File
- Content description 77 kB
- Updated on the site 23.05.2020
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Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)
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Solving a problem in physics section 68 point 8 electr
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Cumulative discount
| 30 $ | the discount is 10% |
| 20 $ | the discount is 7% |
| 18 $ | the discount is 6% |
| 15 $ | the discount is 5% |
| 12 $ | the discount is 4% |
| 9 $ | the discount is 3% |
| 6 $ | the discount is 2% |
| 3 $ | the discount is 1% |
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Your discount: %
Cumulative discount
| 30 $ | the discount is 10% |
| 20 $ | the discount is 7% |
| 18 $ | the discount is 6% |
| 15 $ | the discount is 5% |
| 12 $ | the discount is 4% |
| 9 $ | the discount is 3% |
| 6 $ | the discount is 2% |
| 3 $ | the discount is 1% |
Check your discount
Amount of purchases from the seller: $
Your discount: %