Solving problem N3883 Bayesian probability theory
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3883. For signaling a malfunction in the operation of an automated line, one indicator is used that belongs to probabilities of 0.2; 0.3; and 0.5 to one of three types, for which the probabilities of operation when the normal operation of the line is disturbed are equal to 0.99, respectively; 0.75 and 0.40. Find the probability that the indicator is triggered by a line fault. What is the probability that a type 1 indicator is used for control if it has signaled a malfunction that has occurred?
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- Content type File
- Content description 30 kB
- Updated on the site 08.02.2019
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Detailed solution. Decorated in Microsoft Word 2003 (Quest decided to use the formula editor)
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Solving problem N3883 Bayesian probability theory
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| 20 $ | the discount is 7% |
| 18 $ | the discount is 6% |
| 15 $ | the discount is 5% |
| 12 $ | the discount is 4% |
| 9 $ | the discount is 3% |
| 6 $ | the discount is 2% |
| 3 $ | the discount is 1% |
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Your discount: %
Cumulative discount
| 30 $ | the discount is 10% |
| 20 $ | the discount is 7% |
| 18 $ | the discount is 6% |
| 15 $ | the discount is 5% |
| 12 $ | the discount is 4% |
| 9 $ | the discount is 3% |
| 6 $ | the discount is 2% |
| 3 $ | the discount is 1% |
Check your discount
Amount of purchases from the seller: $
Your discount: %