Solving problem N3915 Bayesian probability theory
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3915. On three machines with identical and independent conditions, parts of the same name are manufactured. On the first machine make 10%, on the second - 30%, on the third - 60% of all parts. The probability of each part to be faultless is 0.7, if it is made on the first machine, 0.8 - if on the second machine, and 0.9 - if on the third machine. The detail taken at random turned out to be faultless. Find the probability that it is made on 2 machines.
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- Content type File
- Content description 28,5 kB
- Updated on the site 12.02.2019
Additional description
Detailed solution. Decorated in Microsoft Word 2003 (Quest decided to use the formula editor)
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Solving problem N3915 Bayesian probability theory
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Sold <10
0 000 X
Secure deal
Instant delivery
Cumulative discount
| 30 $ | the discount is 10% |
| 20 $ | the discount is 7% |
| 18 $ | the discount is 6% |
| 15 $ | the discount is 5% |
| 12 $ | the discount is 4% |
| 9 $ | the discount is 3% |
| 6 $ | the discount is 2% |
| 3 $ | the discount is 1% |
Check your discount
Amount of purchases from the seller: $
Your discount: %
Cumulative discount
| 30 $ | the discount is 10% |
| 20 $ | the discount is 7% |
| 18 $ | the discount is 6% |
| 15 $ | the discount is 5% |
| 12 $ | the discount is 4% |
| 9 $ | the discount is 3% |
| 6 $ | the discount is 2% |
| 3 $ | the discount is 1% |
Check your discount
Amount of purchases from the seller: $
Your discount: %