Task 20306.
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Diatomic gas at a pressure of 440 kPa p1 = volume has V1 = 0,83 m ^ 3, at a pressure p2 = 120 kPa - volume V2 = 0,39 m ^ 3. The transition from the first state to the second was done in two stages: first by the isotherm, and then isochor. The amount of heat absorbed by the gas, Q, gas work A. Determine the increment of internal energy.
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- Content description 176,06 kB
- Updated on the site 30.04.2014
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Detailed solution shorthand terms, formulas, laws used in the decision, the withdrawal of the calculation formula and the response.
If you have any questions to address, please. I´ll try to help.
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