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Diatomic gas at a pressure of 270 kPa p1 = volume has V1 = 0,14 m ^ 3, at a pressure of 320 kPa p2 = - volume V2 = 0,11 m ^ 3. The transition from the first state to the second was done in two stages: first by the isotherm, and then isochor. Determine the amount of heat absorbed by the gas Q.
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- Content type File
- Content description 13,99 kB
- Added to the site 12.01.2016
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Detailed solution shorthand terms, formulas and laws used in the decision, the withdrawal of the calculation formula and the response.
If you have any questions to address, please. I try to help.
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