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Option 4
Followers Operation Predecessors duration Workforce
(Work) (days) (pers.)
A B, C April 5
B D A January 8th
C E, F, G, H A 6 0
D F, G, H B March 2
E I C June 4
F I C, D July 8
G KC, D 1 June
H J C, D March 8
IK E, F April 9
J K H 5 0
K L, M G, I, J March 6
L N K Aug. 4
M K 2 March
N O L 1 August
O N February 3
Build a network model. Run time and resource analysis
Option 4
Operation
(I, j) normal deadlines Deadlines Increased costs
Duration costs Duration costs
(0,1) -A 4210 3280 70
(0,2) -B 8400 6560 80
(1,2) -C 6 400 4.6001 million
(1,4) -D 9540 7600 30
(2,3) -E 4 800 100 January 1100
(2,4) -F 5 150 4240 90
(3,5) -G 3150 3150 -
(4,5) -H 7600 6.75015 million
= 3250 = 4280
The table shows the duration and cost of each operation corresponding to the normal and the most intensive mode of its implementation. To illustrate the effect of accelerating the work on the overall cost, we will take into account the indirect costs of $ 130 den. units / day.
Task: required to determine the minimum cost of schedules that can be implemented in the interval between the points of maximum intensity and normal modes. Find the optimal schedule.
Followers Operation Predecessors duration Workforce
(Work) (days) (pers.)
A B, C April 5
B D A January 8th
C E, F, G, H A 6 0
D F, G, H B March 2
E I C June 4
F I C, D July 8
G KC, D 1 June
H J C, D March 8
IK E, F April 9
J K H 5 0
K L, M G, I, J March 6
L N K Aug. 4
M K 2 March
N O L 1 August
O N February 3
Build a network model. Run time and resource analysis
Option 4
Operation
(I, j) normal deadlines Deadlines Increased costs
Duration costs Duration costs
(0,1) -A 4210 3280 70
(0,2) -B 8400 6560 80
(1,2) -C 6 400 4.6001 million
(1,4) -D 9540 7600 30
(2,3) -E 4 800 100 January 1100
(2,4) -F 5 150 4240 90
(3,5) -G 3150 3150 -
(4,5) -H 7600 6.75015 million
= 3250 = 4280
The table shows the duration and cost of each operation corresponding to the normal and the most intensive mode of its implementation. To illustrate the effect of accelerating the work on the overall cost, we will take into account the indirect costs of $ 130 den. units / day.
Task: required to determine the minimum cost of schedules that can be implemented in the interval between the points of maximum intensity and normal modes. Find the optimal schedule.
Main features
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- Content description 318,33 kB
- Added to the site 20.08.2013
Additional description
Option 4
Limited Liability Company «Jubilee Computer Systems Ltd» performs the order received from its customers. The required information is listed below.
Operation
The period immediately preceding the operation, days Cost for the expected duration, f. cm.
Optimistic most likely pessimistic
A 3 May 13300
In August 1 9700
C 4 5 6 2000
D A 7 8 15 1200
E 2 to 4 12900
F With 8 9 22 2300
G DE 3 April 5400
H, G, F February 1 3300
8100
Indirect costs associated with the implementation of the project amount to £ 300. Art. in a day. The contract concluded with a consumer, agreed that if the order is not made within 20 days, the amount of the penalty will be £ 100. Art. for each subsequent day. Required:
1.Postroit network graph. What is the expected value of the execution time of the entire project? What is the value corresponding to the value?
2. What likelihood that the project will be completed without payment of penalties?
3.Kakova likelihood that the project will be completed in the interval from 21 to
25 days?
Limited Liability Company «Jubilee Computer Systems Ltd» performs the order received from its customers. The required information is listed below.
Operation
The period immediately preceding the operation, days Cost for the expected duration, f. cm.
Optimistic most likely pessimistic
A 3 May 13300
In August 1 9700
C 4 5 6 2000
D A 7 8 15 1200
E 2 to 4 12900
F With 8 9 22 2300
G DE 3 April 5400
H, G, F February 1 3300
8100
Indirect costs associated with the implementation of the project amount to £ 300. Art. in a day. The contract concluded with a consumer, agreed that if the order is not made within 20 days, the amount of the penalty will be £ 100. Art. for each subsequent day. Required:
1.Postroit network graph. What is the expected value of the execution time of the entire project? What is the value corresponding to the value?
2. What likelihood that the project will be completed without payment of penalties?
3.Kakova likelihood that the project will be completed in the interval from 21 to
25 days?
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kerzhaev
1
Cumulative discount
| 30 $ | the discount is 12% |
| 15 $ | the discount is 5% |
| 5 $ | the discount is 1% |
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Amount of purchases from the seller: $
Your discount: %
0.13 $ gift card for a positive review
kerzhaev
1
Cumulative discount
| 30 $ | the discount is 12% |
| 15 $ | the discount is 5% |
| 5 $ | the discount is 1% |
Check your discount
Amount of purchases from the seller: $
Your discount: %
0.13 $ gift card for a positive review