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The air wedge is formed by two glass plates held together at an alpha angle. Light with a wavelength of 0.533 microns is normally incident on the wedge. In reflected light, interference fringes are visible on the surface of the wedge. Band width 2.0 mm. How will the interference pattern change if the space between the plates is filled with water? What will the bandwidth be equal to? The refractive indices of air, water and glass are equal: n = 1, n = 1.33, n = 1.87.
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- Added to the site 06.06.2014
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Detailed solution with a short recording of the conditions, laws and formulas used in the decision, the withdrawal of the calculation formula and the answer.
If you have any questions about the solution, write. I try to help.
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