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123. Solving a chemistry problem
Uploaded:
27.07.2022
Content: 522.rar 20,8 kB
Content: 522.rar 20,8 kB
Product description
The specific electrical conductivity of a saturated solution of BaSO4 is 3.48*10-4 S/m, and that of a solvent (water) is 0.5*10-4 S/m. Calculate the solubility product of this salt, taking the molar conductivity of BaSO4 in a saturated solution equal to the limiting conductivity (limiting conductivities of Ba2 and SO42- ions are 0.012726 and 0.016004 S*m2*mol-1, respectively).
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