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104. Solving a chemistry problem
Uploaded:
01.09.2022
Content: 316.rar 20,74 kB
Content: 316.rar 20,74 kB
Product description
316. The electrical conductivity of a saturated solution of BaSO4 is 3.48 × 10–4 S/m, and that of a solvent (water) is 0.50 × 10–4 S/m. Calculate the solubility product of this salt, assuming that the molar conductivity of BaSO4 in a saturated solution is equal to the limiting conductivity (the limiting conductivities of Ba2 and SO42– ions are 0.012726 and 0.016004 Sm⋅m2⋅mol–1, respectively).
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